If det (A_3x3) = 6, then det (Adj 2A) =

$|\mathrm{A}{|}_{3\times 3}=6,|\mathrm{Adj}|=?$
Adj(KA) = K^n-1AdjA
Adj(2A) = 2^3-1Adj= 4AdjA
$|\mathrm{Adj}(2\mathrm{A}\left)\right|=|4\mathrm{Adj}\mathrm{A}|=4^3|\mathrm{Adj}\mathrm{A}|=4^3|6{|}^2$
= 2⁶ x 2² x 3² = 2⁸ x 3²