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Q.

If displacement of a particle is directly proportional to the square of time. Then particle is moving with

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a

Uniform acceleration

b

Uniform velocity

c

Variable acceleration

d

Variable acceleration but uniform velocity

answer is A.

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Detailed Solution

Given that $x \propto t^{2}$ or $x = K t^{2}$ (where K= constant)

Velocity (v) $= \frac{d x}{d t} = 2 K t$ and Acceleration (a) $= \frac{d υ}{d t} = 2 K$

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