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Q.

If dxx+x7=p(x), then x6x+x7dx=

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a

logxpx+c

b

logx+px+c

c

xp(x)+c

d

x+p(x)+c

answer is A.

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Detailed Solution

x7xx+x7dx=x+x7xxx+x7dx=1x1x+x7dx

=logxpx+c

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If ∫dxx+x7=p(x), then ∫x6x+x7dx=