Q.

If e and e1 are the eccentricities of the ellipse 5x2 +9y2 =45 and the hyperbola 5x2 4y2 =45 then e e1 =

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a

9

b

5

c

4

d

1

answer is D.

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Detailed Solution

Given ellipse x29+y25=1.(a>b)  e= 9-59=49=23 Given Hyperbola x29-y2454=1 Now  e1=9+4549=36+4536=8136=96=32 Now  e e1=23 32=1

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