If e, $ε$ ₀, h and c respectively represent electronic charge, permittivity of free space, Planck's constant and speed of light, then $\frac{e^{2}}{ε_{0} h c}$ has the dimensions of:

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Pressure

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Angular momentum

Angle

answer is D.

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Detailed Solution

Dimensions of $ε_{0}$ and h are $M^{- 1} L^{- 3} T^{4} A^{2}$ and ${ML}^{2} T^{- 1}$ respectively.

$[\frac{e^{2}}{\in_{0} hc}] = [\frac{e^{2} {Fd}^{2}}{q^{2} hc}] = [\frac{{Fd}^{2}}{hc}] = \frac{{MLT}^{- 2} L^{2}}{{ML}^{2} T^{- 1} {LT}^{- 1}} = M^{0} L^{0} T^{0}$

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