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Q.

If $e_{1} a n d e_{2}$ are eccentricities of hyperbola and its conjugate hyperbola respectively then $\frac{1}{e_{1}^{2}} + \frac{1}{e_{2}^{2}} =$

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Detailed Solution

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$e_{1} = \frac{a^{2} + b^{2}}{a^{2}} e_{2} = \frac{a^{2} + b^{2}}{b^{2}}$

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