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If electric potential V at nay point $(x, y, z)$ all in meters in space is given by $V = 4 x^{2} v o l t .$ Calculate the electric field at the point $(1 m, 0 m, 2 m)$

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$6 V / m$

$4 V / m$

$2 V / m$

$8 V / m$

answer is A.

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Detailed Solution

$E = \frac{- d V}{d r} \Rightarrow F_{x} = \frac{- d}{d x} (4 x^{2}) = - 8 x, E_{y} = 0, E_{z} = 0$

So, $E = E x i + E y j + E z k = - 8 x i$

magnitude $= 8 V / m$

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