If electronegativity of $X$ be $3.2$ and that of $Y$ be $2.2$, the percentage ionic character of $XY$ is :

 Electronegativity of $X$ be $3.2$ and that of $Y$ be $2.2$, the percentage ionic character of $XY$ is 19.5.

$\mathrm{\%}\text{ Ionic charecter }=16x\left|E_x-E_y\right|+35{\left|E_x{ϵ}_y\right|}^2$

$\begin{array}{l}=|6\times |3.2-2\cdot 2|+3.5|3.2-2\cdot 2{|}^2\\ =16\times 1+3.5\\ =16+3.5\end{array}$

$=19.5$

Hence, the option A is correct.