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Q.

If enthalpy of vaporization of water is 186.5 kJ/mol, the entropy of vaporization will be :

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a

1.5

b

1.0

c

2.0

d

0.5

answer is A.

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Detailed Solution

From second law of thermodynamics,

$∆ s = \frac{∆ H}{T}$

$T = 373 K a n d ∆ H = 186.5 K J / m o l e$

$∴ ∆ S = \frac{186.5}{373} = 0.5 K J / m o l e^{- 1}$

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