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Q.

If equations bx2+acx+b2c=0 and cx2+abx+b2c=0 have a common root (when a,b,c are non-zero distinct real numbers), then which of the following is not true.

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a

ac+bc+ab=0

b

1bc2+1cb2+1a2c=0

c

1ac2+1ba2+1cb2=0

d

a2b+a2c+b2c=0

answer is C.

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Detailed Solution

bx2+acx+b2c=0   and  cx2+abx+b2c=0

Eliminating x2, we get x=α=a which is  common root

Put x=a in first equation

a2b+a2c+b2c=0(i)

On dividing (i)  by a2b2c2 we get

1bc2+1cb2+1a2c=0

On dividing (i) by abc

ac+ab+bc=0

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