If F¯=(2i^−3j^)N and r¯=(3i^+2j^)m then torque "τ" is

Torque τ=r¯×p¯r¯×p¯=ijk3202−0τ=r¯×p¯=i(0)−j(0)+k(−9−4)=−13k

If F¯=(2i^−3j^)N and r¯=(3i^+2j^)m then torque "τ" is

Torque τ=r¯×p¯r¯×p¯=ijk3202−0τ=r¯×p¯=i(0)−j(0)+k(−9−4)=−13k

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If $\bar{F} = (2 \hat{i} - 3 \hat{j}) N and \bar{r} = (3 \hat{i} + 2 \hat{j}) m$ then torque " $τ$ " is

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12 K

13 K

-12 K

-13 K

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Detailed Solution

Torque $τ = \bar{r} \times \bar{p}$
$\begin{array}{l} \bar{r} \times \bar{p} = |\begin{array}{lll} i & j & k \\ 3 & 2 & 0 \\ 2 & - & 0 \end{array}| \\ τ = \bar{r} \times \bar{p} = i (0) - j (0) + k (- 9 - 4) = - 13 k \end{array}$

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