If f : R→R , g :R→R are two function defined by f(x)=3x−2 , g (x)= x2+1 , then (gof−1)(1)

f(x)=3x-2, g(x)=x2+1 f−1(x)=x+23⇒f−1(1)=33=1 (gof−1)(1)=g[f−1(1)]=g(1)=1+1=2

If f : R→R , g :R→R are two function defined by f(x)=3x−2 , g (x)= x2+1 , then (gof−1)(1)

f(x)=3x-2, g(x)=x2+1 f−1(x)=x+23⇒f−1(1)=33=1 (gof−1)(1)=g[f−1(1)]=g(1)=1+1=2

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If f : $R \to R$ , g : $R \to R$ are two function defined by f(x)= $3 x - 2$ , g (x)= $x^{2} + 1$ ,
then $(g o f^{- 1}) (1)$

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$f (x) = 3 x - 2, g (x) = x^{2} + 1 f^{- 1} (x) = \frac{x + 2}{3} \Rightarrow f^{- 1} (1) = \frac{3}{3} = 1$

$(g o f^{- 1}) (1) = g [f^{- 1} (1)] = g (1) = 1 + 1 = 2$

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If f : R→R , g :R→R are two function defined by f(x)=3x−2 , g (x)= x2+1 , then (gof−1)(1)

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If f : $R \to R$ , g : $R \to R$ are two function defined by f(x)= $3 x - 2$ , g (x)= $x^{2} + 1$ ,
then $(g o f^{- 1}) (1)$