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Q.

If  f:R+R be an increasing function such that xf(x)+2>0  and  f(x).f(xf(x)+4x)=1 then match the following

Column – IColumn – II
A) The value of [1f(1)]  ([.] GIF)P) 0
B) The value of  |[f(12)]| equals ([.] GIF)Q) 1
C) The value of [f'(1)]  is ([.] GIF) R) 2
D) Number of solutions of  sinxf(8)=0 in [π,2π]  is S) 3
  T)4

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a

A – R, B – S, C – R, D – T 

b

A – R, B – T, C – Q, D – T

c

A – R, B – Q, C – S, D – T

d

A – S, B – T, C – S, D – T

answer is C.

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Detailed Solution

Replace  x by  f(x)+4x
 f(f(x)+4x).f(f(x)+4x+4f(x)+4x)=1    ff(x).f(1f(x)+4xxf(x)+4)=1    1f(x)+4xxf(x)+4=x1t+4xxt+4=x    xt+4+4xt=(xt)2+4xt    (xt)2(xt)4=0xt=1±1+162   t=1172xf(x)=1172x(f)
 
 
 
 
 
 

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