If f:R→R is defined by f(x)=x−[x]−12 for x∈R where [x] is the greatest integer not exceeding x then {x∈R:f(x)=12}=

f(x)=x−[x]−12 f(x)=12⇒x−[x]=1 But x−[x]∈[0,1)Required set : ϕ

If f:R→R is defined by f(x)=x−[x]−12 for x∈R where [x] is the greatest integer not exceeding x then {x∈R:f(x)=12}=

f(x)=x−[x]−12 f(x)=12⇒x−[x]=1 But x−[x]∈[0,1)Required set : ϕ

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If $f : R \to R$ is defined by $f (x) = x - [x] - \frac{1}{2}$ for $x \in R$ where [x] is the greatest integer not exceeding x then ${x \in R : f (x) = \frac{1}{2}} =$

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$f (x) = x - [x] - \frac{1}{2} f (x) = \frac{1}{2} \Rightarrow x - [x] = 1 B u t x - [x] \in [0, 1)$
Required set : $ϕ$

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If f:R→R is defined by f(x)=x−[x]−12 for x∈R where [x] is the greatest integer not exceeding x then {x∈R:f(x)=12}=

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If $f : R \to R$ is defined by $f (x) = x - [x] - \frac{1}{2}$ for $x \in R$ where [x] is the greatest integer not exceeding x then ${x \in R : f (x) = \frac{1}{2}} =$