If f(x)={1+kx−1−kxx,for−1≤x<0(x−3)2,for0≤x≤1 is continuous at x=0 then K=

limx→0−f(x)=limx→0+f(x) , f(x) is continuous at ‘0’

If f(x)={1+kx−1−kxx,for−1≤x<0(x−3)2,for0≤x≤1 is continuous at x=0 then K=

limx→0−f(x)=limx→0+f(x) , f(x) is continuous at ‘0’

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If $f (x) = {\begin{matrix} \frac{\sqrt{1 + k x} - \sqrt{1 - k x}}{x}, & f o r & - 1 \leq x < 0 \\ {(x - 3)}^{2}, & f o r & 0 \leq x \leq 1 \end{matrix}$ is continuous at $x = 0$ then K=

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$\lim_{x \to 0^{-}} f (x) = \lim_{x \to 0^{+}} f (x)$ , $f (x)$ is continuous at ‘0’

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If f(x)={1+kx−1−kxx,for−1≤x<0(x−3)2,for0≤x≤1 is continuous at x=0 then K=

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If $f (x) = {\begin{matrix} \frac{\sqrt{1 + k x} - \sqrt{1 - k x}}{x}, & f o r & - 1 \leq x < 0 \\ {(x - 3)}^{2}, & f o r & 0 \leq x \leq 1 \end{matrix}$ is continuous at $x = 0$ then K=