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If $F (x) = [\begin{array}{ccc} \cos x & - \sin x & 0 \\ \sin x & \cos x & 0 \\ 0 & 0 & 1 \end{array}]$ and $G (x) = [\begin{array}{llc} \cos x & 0 & \sin x \\ 0 & 1 & 0 \\ - \sin x & 0 & \cos x \end{array}]$ Then [F(x)G(x)]^-1 =

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G(-x)F(-x)

{F(x){G(x)}^-1

[G(X)]{F(x)}

F(x).G(x)

answer is A.

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Detailed Solution

[F(x)G(x)]^-1 = G(x)^-1F(x)^-1 =G(x)F(x)

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