If  $f\left(x\right)$ is a real valued function defined by $f\left(x\right)=\frac{a{x}^{10}+b{x}^8+c{x}^6+d{x}^4+e{x}^2+12x+15}{x}$$(x\ne 0) and f\left(4\right)=-4$ then $f(-4)=$

$\because f\left(x\right)=a{x}^9+b{x}^7+c{x}^5+d{x}^3+ex+12+\frac{15}{x}$

$\because f(-x)=-a{x}^9-b{x}^7-c{x}^5-d{x}^3-ex+12-\frac{15}{x}$

$\therefore f\left(x\right)+f(-x)=24$

$f\left(4\right)+f(-4)=24$

$f(-4)=24-f\left(4\right)=24-(-4)\Rightarrow 24+4=28$