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Q.

If f(x) = sinx + cosx and g(x) = |x|x,    x02,    x=0 then the value of π/42πgof(x)dx=

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a

3π4

b

π4

c

π

d

3π

answer is B.

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Detailed Solution

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g(x)=xx=1,x>02,x=0xx=1,x<0 ;g(f(x))=1,sinx+cosx>02,sinx+cosx=01,sinx+cosx<0  From π4to3π4,sinx+cosx>0  From 3π4 to 7π4,sinx+cosx<0; From  7π4 to 2π,sinx+cosx>0 π42π/4g(f(x))dx=π/43π/41dx+3π/47π/41dx+7π/42π1dx=π4

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