Q.

Iff(x)=sinx+cosx,g(x)=x21,  theng(f(x))is  invertible  in  the  domain

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a

[π4,  π4]

b

[0,  π]

c

[π2,  π2]

d

[0,π2]

answer is B.

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Detailed Solution

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f(x)=sinx+cosx,g(x)=x21g(f(x))=g(sinx+cosx)=(sinx+cosx)21=sin2x+cos2x+2sinxcosx1=2sinxcosx=sin2xit  π4xπ4  thensin2x  isoneoneandontog(f(x))  is  invertible  in  π4xπ4

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