If f(x)=x+1x−1(x≠1) then (fofof)x=

(f∘f)x=fx+1x−1=x+1x−1+1x+1x−1−1=2x2=x(f∘f∘f)x=f(x)=x+1x−1

If f(x)=x+1x−1(x≠1) then (fofof)x=

(f∘f)x=fx+1x−1=x+1x−1+1x+1x−1−1=2x2=x(f∘f∘f)x=f(x)=x+1x−1

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If $f (x) = \frac{x + 1}{x - 1} (x \neq 1)$ then $(f o f o f) x =$

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$\begin{array}{l} (f \circ f) x = f [\frac{x + 1}{x - 1}] = \frac{\frac{x + 1}{x - 1} + 1}{\frac{x + 1}{x - 1} - 1} = \frac{2 x}{2} = x \\ (f \circ f \circ f) x = f (x) = \frac{x + 1}{x - 1} \end{array}$

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If $f (x) = \frac{x + 1}{x - 1} (x \neq 1)$ then $(f o f o f) x =$