If following proceed in forward side,

$$\begin{gathered} {\mathrm{HNO}}_2+\mathrm{HF}\rightleftharpoons {\mathrm{H}}_2{\mathrm{F}}^{+}+{\mathrm{NO}}_2^{-} \\ {\mathrm{CH}}_3\mathrm{COOH}+\mathrm{HF}\rightleftharpoons {\mathrm{F}}^{-}+{\mathrm{CH}}_3{\mathrm{COOH}}_2^{+} \\ {\mathrm{H}}_2\mathrm{O}+{\mathrm{CH}}_3\mathrm{COOH}\rightleftharpoons {\mathrm{H}}_3{\mathrm{O}}^{+}+{\mathrm{CH}}_3{\mathrm{COO}}^{-} \end{gathered}$$

then, the increasing order of acidic strength is

HNO₂ is proton donor and is thus stronger acid than HF.
HF is proton donor and is thus stronger acid than CH₃COOH.
CH₃COOH is proton donor and is thus stronger acid than H₂O.

$$\begin{gathered} {\mathrm{HNO}}_2>\mathrm{HF} \\ \mathrm{HF}>{\mathrm{CH}}_3\mathrm{COOH} \\ {\mathrm{CH}}_3\mathrm{COOH}>{\mathrm{H}}_2\mathrm{O} \end{gathered}$$