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If force F, length L and time T are chosen as fundamental quantities, the dimensional formula of Mass is

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$[F L T]$

$[F^{- 1} L^{- 1} T^{- 2}]$

$[F^{- 2} L^{- 2} T^{- 2}]$

$[F^{1} L^{- 1} T^{2}]$

answer is D.

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Detailed Solution

$M^{1} L^{0} T^{0} = {[M^{1} L^{1} T^{- 2}]}^{x} L^{y} T^{Z}$

$x = 1 x + y = 0$

$- 2 x + z = 0$

$x = 1; y = - 1; z = 2$

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