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Q.

If forces of magnitudes 6 and 7 units acting in the directions 

 i - 2 j + 2k and 2 i - 3 j - 6k respectively act on particle which is displaced   from P (2, -1, -3) to Q (5, -1, 1) then the work done by the forces is

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a

7 units 
 

b

4 units 
 

c

–7 units

d

–4 units 
 

answer is A.

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Detailed Solution

F=6i-2j+2k3+72i-3j-6k7     =4i-7j-2k PQ=3i+4k work done=F.PQ=12-8=4

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