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If four angles of a cyclic quadrilateral are $(2 x - 1 °), (y + 5); (2 y + 15) °$ and $(4 x - 7) °$ , then

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An Intiative by Sri Chaitanya

x = 50, y = 33

x = 40, y = 43

x = 30, y = 53

x = 33, y = 50

answer is A.

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Detailed Solution

2 x + 2 y + 14 = 180

$x + y + 7 = 90$

$x + y - 83 = 0 \to (1)$

$4 x + y - 2 = 180$

$4 x + y - 182 = 0 \to (2)$

Solve (1) and (2), we get

$x = 33, y = 50$

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