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If four dice are thrown simultaneously, then that probability that none of the dice shows the number 1 on its face is

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$\frac{625}{1296}$

$\frac{625}{2592}$

$\frac{125}{648}$

$\frac{1250}{1296}$

answer is A.

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Detailed Solution

A die rolled showing a number 1 is $\frac{1}{6}$

Not showing a number 1 is $\frac{5}{6}$

When four dies are rolled then

probability that none of the dice shows the number 1 is $\frac{625}{1296}$

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