If four dice are thrown simultaneously, then that probability that none of the dice shows the number 1 on its face is 

A die rolled showing a number 1 is $\frac{1}{6}$

Not showing a number 1 is $\frac{5}{6}$

When four dies are rolled then 

probability that none of the dice shows the number 1 is $\frac{625}{1296}$