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Q.

If four distinct points with position vectors  a,b,c and d are coplanar, then [abc] is equal to

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a

[bcd]+[dac]+[dba]

b

[dca]+[bda]+[cdb]

c

[adb]+[dca]+[dbc]

d

[dba]+[acd]+[dbc]

answer is C.

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Detailed Solution

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(a¯b¯).(a¯c¯)×(a¯d¯)=0(a¯b¯).(a¯×d¯c¯×a¯+c¯×d¯)=0 [a¯c¯d¯]+[b¯a¯d¯]+[b¯c¯a¯][b¯c¯d¯]=0 [a¯  b¯c¯]=[d¯c¯a¯]+[b¯d¯a¯]+[c¯  d¯b¯]

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