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Q.

If, from 10 moles ${NH}_{3}$ and 5 moles of $H_{2} {SO}_{4}$ , all the H-atoms are removed in order to form $H_{2}$ gas, then find the number of moles of $H_{2}$ formed.

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answer is 20.

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Detailed Solution

We are substitute the value in these form we get

$\frac{10 \times 3 + 5 \times 2}{2} = 20$

the number of moles of $H_{2}$ formed = 20 moles

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