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If from each of 3 boxes containing 3 white and 1black, 2 white and 2 black, 1 white and 3 black balls,one ball is drawn then the probability of drawing 2 white and 1 black ball is

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$\frac{13}{32}$

$\frac{1}{4}$

$\frac{1}{32}$

$\frac{3}{16}$

answer is A.

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Detailed Solution

3W 1B	2W 2B	1W 3B
Case (i) W	W	B
Case (ii) W	B	W
Case (iii) B	W	W

The desired probability is

= $\frac{3}{4} \cdot \frac{2}{4} \cdot \frac{3}{4} + \frac{3}{4} \cdot \frac{2}{4} \cdot \frac{1}{4} + \frac{1}{4} \cdot \frac{2}{4} \cdot \frac{1}{4} = \frac{13}{32} .$

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