If from $3$ moles ${MgSO}_{4} \cdot 7 H_{2} O,$ all the $' O'$ atoms are taken out and converted into ozone find the number of moles of $O_{3}$ formed.

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answer is 11.

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Detailed Solution

The number of oxygen atoms in hepta hydrated magnesium sulfate is 7+4=11.

Thus one mole of ${MgSO}_{4} \cdot 7 H_{2} O$ has 11 oxygen atoms.

Three moles of ${MgSO}_{4} \cdot 7 H_{2} O$ will contain 3×11=33 oxygen atoms.

Now one mole of ozone has three oxygen atoms. 33 oxygen atoms will have 33/3=11 mole.

Thus 11N or $11 \tilde{A} 6.023 \tilde{A} 10^{23}$ molecules of oxygen atoms will formed.

$3 \times 11 \times \frac{1}{3}$

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