If f:R→R , g:R→R functions defined by f(x)=5x−1, g(x)=x2+1 then (gof−1)(2)=

f(x)=5x-1f−1(x)=x+15 g(x)=x2 +1 (gof−1)(2)=g(35)=3425

If f:R→R , g:R→R functions defined by f(x)=5x−1, g(x)=x2+1 then (gof−1)(2)=

f(x)=5x-1f−1(x)=x+15 g(x)=x2 +1 (gof−1)(2)=g(35)=3425

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If _{$f : R \to R$} , _{$g : R \to R$} functions defined by _{$f (x) = 5 x - 1, g (x) = x^{2} + 1$} then _{$(g o f^{- 1}) (2) =$}

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_{$\frac{25}{3}$}

_{$\frac{34}{25}$}

_{$\frac{16}{9}$}

_{$\frac{4}{3}$}

answer is A.

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Detailed Solution

f(x)=5x-1
$f^{- 1} (x) = \frac{x + 1}{5}$

g(x)=x² +1

$(g o f^{- 1}) (2) = g (\frac{3}{5}) = \frac{34}{25}$

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If f:R→R , g:R→R functions defined by f(x)=5x−1, g(x)=x2+1 then (gof−1)(2)=

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If _{$f : R \to R$} , _{$g : R \to R$} functions defined by _{$f (x) = 5 x - 1, g (x) = x^{2} + 1$} then _{$(g o f^{- 1}) (2) =$}