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If $f : R \to R$ is defined by $f (x) = 3 x - 2$ , then $(f o f) (x) + 2 =$

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- f (x)

3 f (x)

f (x)

2 f (x)

answer is C.

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Detailed Solution

f [f (x)] = f (3 x - 2)

$= 3 (3 x - 2) - 2$

$= 9 x - 6 - 2$

$= 9 x - 8$

$f o f (x) = 9 x - 8$

$f o f (x) + 2 = 9 x - 8 + 2$

$= 9 x - 6$

$= 3 (3 x - 2)$

$= 3 f (x)$

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