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Q.

If f(θ)=(sinθ+cosecθ)2+(cosθ+secθ)2 , then minimum value of f(θ) is k, then k is divisible by

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a

1

b

3

c

9

d

5

answer is C.

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Detailed Solution

f(θ)=(sinθ+cosecθ)2+(cosθ+secθ)2

f(θ)=sin2θ+cosec2θ+2+cos2θ+sec2θ+2

=5+1+cot2θ+1+tan2θ

=7+tan2θ+cot2θ

We know tan2θ+cot2θ2tan2θcot2θ

tan2θ+cot2θ2

Minimum value of f(0)=7+2=9

 k=9  is divisible by 1,3,9

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