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Q.

If  fx=ax7+bx3+cx5  where  a,b,cR  and  f7=7  then the range of  f7+17cosx is            

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a

[-1, 1]

b

[-34, 0] 

c

[-34, 34]

d

[0, 34]

answer is B.

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Detailed Solution

fx+fx=10 and sub  x=7  f7=17,  cosx[1,1]

   f7+17  cosx=1717,  17+17=34,  0

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