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Q.

If fx=cosx.cos2x. cos4x.cos8x.cos16x then f'π4is 

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a

12

b

0

c

1

d

2

answer is A.

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Detailed Solution

f(x)=sin32x32sinx
f1(x)=cos32xsinx132sin(32x)cosx
f1(π4)=   2

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