Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

If f(x)= xC0 xC1 x+1C12xC12xC22(x+1)C26xC26xC36(x+1)C3, then f(200) is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

b

c

d

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

 xC0 xC1 x+1C12xC12xC22(x+1)C26xC26xC36(x+1)C31xx+12xx(x1)(x+1)(x)3x(x1)x(x1)(x2)(x+1)x(x1)

C3C3C1+C21x02xx(x1)03x(x1)x(x1)(x1)0=0

For any value of x  f(x) = 0. 

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring
If f(x)= xC0 xC1 x+1C12xC12xC22(x+1)C26xC26xC36(x+1)C3, then f(200) is