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Q.

If f(x)=4x2+3x-7 and α is a common root of the equation x2-3x+2=0 and x2+2x-3=0 then find the value of f(α)


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a

0

b

1

c

2

d

3 

answer is A.

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Detailed Solution

Firstly we will take the equation, x2-3x+2=0 Now, we will calculate the roots by using the middle term method.
In this method we will find out two numbers whose sum is −3 and product is 2.
So, we are getting with the two numbers which are −2 and −1
x2-x-2x+2=0 Taking out common in the pairs of 2 we get,
x(x1)2(x1)=0
Taking 2 same factors one time we get,
(x1)(x2)=0
Now, we will separate the above two factors to calculate the value of x.
Firstly we will take the factor x−1=0
Taking 1 on the right side we get,
Therefore, x=1
Secondly we will take the factor x−2=0
Taking 2 on the right side we get,
Therefore, x=2
Hence, the value of x=1,2
Then we will take the equation, x2+2x-3=0
Now, we will calculate the roots by splitting the middle term method.
In this method we will find out two numbers whose sum is 2 and product is −3.
So, we are getting with the two numbers which are −1 and 3
x2-x+3x-3=0 Taking out common in the pairs of 2 we get,
x(x1)+3(x1)=0
Taking 2 same factors one time we get,
(x1)(x+3)=0
Now, we will separate the above two factors to calculate the value of p.
Firstly we will take the factor x−1=0
Taking 1 on the right side we get,
Therefore, x=1
Secondly we will take the factor x+3=0
Taking 3 on the right side we get,
Therefore, x= −3
Hence, the value of x= 1, −3
As it is given in the question that x2-3x+2=0  and x2+2x-3=0 and there is a common root that is α.
But, it is clear from the calculated roots that α = 1(As 1 is common root in both the equations)
So, we will calculate f(α)= f(1) by substituting 1 in the given equation that is f(x)= 4x2+3x-7
After substituting we get,
f(1)= 4(1)2+3(1)-7
On simplifying we get, f(1)=7−7= 0
Hence, the value of f(α)=f(1)= 0
 
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If f(x)=4x2+3x-7 and α is a common root of the equation x2-3x+2=0 and x2+2x-3=0 then find the value of f(α)