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Q.

If g is the acceleration due to gravity on earth's surface, the gain of the potential energy of an object of mass m raised from the surface bf the earth to a height equal to the radius R of the earth is :

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a

2mgR

b

mgR

c

$\frac{1}{2} mgR$

d

$\frac{1}{4} mgR$

answer is C.

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Detailed Solution

Gain in PE $= - \frac{GMm}{2 R} - (- \frac{GMm}{R}) = \frac{GMm}{2 R} = \frac{1}{2} mgR$

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