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If $H . C . F$ of two numbers is $32$ and $L . C . M .$ is $192$ and one of the numbers is $64$ , then the sum of the numbers is

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192 - 32

2 (64) + 32

3 (32) + 64

150

answer is C, A, B.

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Detailed Solution

The

H . C . F

of two numbers is

32

The $L . C . M .$ of two numbers is $192$

One of the numbers is $64$

The product of two numbers $=$ The product Their $L . C . M .$ and $H . C . F$

$a b =$ The product Their $L . C . M .$ and $H . C . F$

$64 \times b = 32 \times 192$

$b = \frac{32 \times 192}{64}$

$b = 96$

$∴$ other number $= 96$

The sum of the numbers $a + b = 64 + 96 = 160$

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