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Q.

If HCF of 210 and 55 is expressed in the form of $210 \times 5 + 55 y$

Find the value of $y^{2} .$

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a

381

b

368

c

361

d

19

answer is C.

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Detailed Solution

Here, Factors of 210=1×2×3×5×7
Factors of 55=1×5×11
Common factors = 1, 5

∴

HCF =1×5=5
according to equation,

5 = 210 \times 5 + 55 y

1 = 210 + 11 y

1 - 210 = 11 y

- 209 = 11 y

\frac{- 209}{11} = y

y = (- 19)

Now,

y^{2} = (- 19) (- 19)

y^{2} = 361

Correct option is 3.

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If HCF of 210 and 55 is expressed in the form of 210×5+55yFind the value of y2.