Q.

If H.C.F of two numbers is 32 and L.C.M. is 192 and one of the numbers is 64, then sum of the numbers is

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a

2(64)+32

b

150

c

3(32)+64

d

19232

answer is C.

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Detailed Solution

H.C.F of two numbers is 32

L.C.M of two numbers is 192

one of the numbers is 64

The product of two numbers = product of their L.C.M and H.C.F

32×192=64×b

32×19264=b

b=96

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