If $H^{+}$concentration of the solution is $1\times {10}^{-2}\mathit{ mol }{l}^{-1}$.The pH value for it will be

The pH of the solution for which $H^{+}$ concentration = $1\times {10}^{-2}\mathit{ mol }{l}^{-1}$ is 2.
$\left[H^{+}\right]=1.0\times {10}^{-2}\mathit{mol }{l}^{-1}$  

pH = $-\mathit{ log }{H}^{+}$       

  $\Rightarrow -\mathit{log }\left(1\times {10}^{-2}\right)$       

   $\Rightarrow -\left(-2\right)\mathit{ log }10$     

     ⇒ $2\mathit{ log }10$        

  $\Rightarrow 2\left(1\right)\mathit{ }$(since log 10=1)

      $\Rightarrow 2$