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Q.

If heat of dissociation of CHCl2COOH is 0.7 kcal/mole then, ΔH for the reaction :

CHCl2COOH+KOH⟶CHCl2COOK+H2O

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a

−13 kcal

b

13 kcal

c

−14.4 kcal

d

−13.7 kcal

answer is A.

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Detailed Solution

Let H is the heat needed to dissociate weak base/acid. Thus,

ΔH=−13.7+(H)ΔH=−13.7+.7ΔH=−13 Kcal

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