If higher powers of x² are neglected, then the value of log(1+x²) – log (1+x) – log (1–x)=

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x²

$\frac{1}{x^{2}}$

2x²

3x²

answer is C.

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Detailed Solution

$\begin{array}{rcl} \log (1 + x^{2}) - \log (1 + x) - \log (1 - x) \\ = & (+ x^{2}) - (x - \frac{x^{2}}{2}) + (x + \frac{x^{2}}{2}) \\ = & 2 x^{2} \end{array}$

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