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Q.

If   ΔHlattice  and ΔHhydration  of NaCl are respectively 778 and -774.6 kJ/mol and   ΔSdissolution of at 298 K is 43 J/mol. The value of   ΔG0for dissolution of 1 mol of NaCl is ____?

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a

-9.114 kJ

b

-7.114 kJ

c

-11.14 kJ

d

+9.114 kJ

answer is A.

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Detailed Solution

ΔHdiss.=ΔHLE+ΔHHyd =778+(-774.3)=3.7 kJ ΔGdiss. =ΔHdiss. -TΔSdiss                =3700-298×43               =-9.11  kJ

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