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Q.

If I=dxsecx+cosecx, then I equals

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a

12[sinxcosx]12log|cosec(x+π4)cot(x+π4)|+C

b

12(cosx+sinx12log(cosecxcosx))+C

c

12(sinx+cosx+12log|cosecxcosx|)+C

d

12(sinxcosx12log|cosecx+cotx|)+C

answer is D.

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Detailed Solution

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I=sinxcosxsinx+cosxdx

=12(sinx+cosx)21sinx+cosxdx

=12[sinx+cosx12sin(x+π/4)]dx

=12[sinxcosx]122log|cosec(x+π/4)cot(x+π/4)|+C

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