If $\mathrm{I}=\int \frac{\mathrm{dx}}{\sqrt[3]{{\sin }^{11}\mathrm{xcos}\mathrm{x}}}=\mathrm{A}(\tan \mathrm{x}{)}^{-\frac{8}{3}}+\mathrm{B}(\tan \mathrm{x}{)}^{-\frac{2}{3}}+\mathrm{c}$ then the value of $\left|4A+B\right|$is ________.

$I=\int \frac{dx}{{\sin }^{11/3}x{\cos }^{1/3}x}$

$=\int \frac{dx}{{\tan }^{11/3}x{\cos }^{4}x}$

$=\int \frac{\left(1+{\tan }^{2}x\right){\sec }^{2}xdx}{{\tan }^{11/3}x}$

$=\int \frac{\left(1+t^2\right)dt}{t^{11/3}}$   $\text{ (where }\tan x=t)$

$=-\frac{3}{8}{t}^{-\frac{8}{3}}-\frac{3}{2}{t}^{-\frac{2}{3}}+c\text{, where }t=\tan x$

$\therefore 4A+B=-3$