If in the reaction N2O4⇌2NO2, α is degree of dissociation of N2O4, then the number of molecules at equilibrium will be:

N2O411-α⇌2NO202α∴ Total mole at equilibrium = 1-α+2α=1+α

If in the reaction N2O4⇌2NO2, α is degree of dissociation of N2O4, then the number of molecules at equilibrium will be:

N2O411-α⇌2NO202α∴ Total mole at equilibrium = 1-α+2α=1+α

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If in the reaction $N_{2} O_{4} ⇌ 2 {NO}_{2}$ , α is degree of dissociation of N₂O₄, then the number of molecules at equilibrium will be:

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(1-α)²

(1+α)

answer is D.

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$\underset{1 - α}{\underset{1}{N_{2} O_{4}}} ⇌ \underset{2 α}{\underset{0}{2 {NO}_{2}}}$
$∴$ Total mole at equilibrium = 1-α+2α=1+α

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If in the reaction N2O4⇌2NO2, α is degree of dissociation of N2O4, then the number of molecules at equilibrium will be:

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If in the reaction $N_{2} O_{4} ⇌ 2 {NO}_{2}$ , α is degree of dissociation of N₂O₄, then the number of molecules at equilibrium will be: