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Q.

If initial rate of effusion ratio $\frac{r_{C H_{4}}}{r_{H e}}$ for $C H_{4}$ and He is $2 : 1$ , at certain temperature, then mole fraction of $C H_{4}$ in initial mixture is _______________

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answer is 0.8.

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Detailed Solution

$\frac{r_{C H_{4}}}{r_{H e}} = \frac{n_{C H_{4}}}{n_{H e}} \sqrt{\frac{M_{H e}}{M_{C H_{4}}}}$
$\frac{2}{1} = \frac{n_{C H_{4}}}{n_{H e}} \sqrt{\frac{4}{16}} = \frac{n_{C H_{4}}}{n_{H e}} \times \frac{1}{2}$
$\frac{n_{C H_{4}}}{n_{H e}} = 4$
$∴$ mole fraction of $C H_{4} = \frac{4}{5} = 0.8$

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If initial rate of effusion ratio rCH4rHe for CH4 and He is 2:1 , at certain temperature, then mole fraction of CH4 in initial mixture is _______________