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If intensity of laser is $(\frac{315}{π}) w / m^{2}$ . Then amplitude electric field associated with this source is close to the nearest integer is __v/m

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175

170

275

270

answer is C.

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Detailed Solution

$I = \frac{1}{2} ε_{0} {E^{2}}_{r m s} C E_{r m s} = 275 V / m$

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