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If I_obe the intensity of the principle maximum in the single slit diffraction pattern, then what will be its intensity when the slit width is doubled ?

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$I_{0}$

$I_{0} / 2$

${4I}_{0}$

$2 I_{0}$

answer is A.

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Detailed Solution

ID case of single slit
$I = I_{0} {(\frac{\sin α}{α})}^{2} where α = \frac{π}{λ} (\frac{d y}{D}) For principal maximum y = 0, i.e., α = 0 Hence, intensity will remain the sa m e .$

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